Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m/s. What is the phase difference between the oscillations of two points?
A
B
C
π
D
Text Solution
Verified by ExpertsThe correct answer is:
B
Phase difference
= 
× path difference
Path difference between two points
Δ x = 15 – 10 = 5 m
Time period, T = 0.05 s
⇒ frequency n = 
= 20 Hz
Velocity, v = 300 m/s
∴ Wavelength, λ = 
= 15 m
Hence, phase difference
Δφ = 
= 
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