The Young’s double slit experiment is performed with blue and with green light of wavelengths 4360 Å and 5460 Å respectively. If X is the distance of 4th maximum from the central one, then :
Text Solution
Verified by ExpertsThe correct answer is:
C
Fourth maxima will be at y = 4 β .
y = 4 β .
⇒ y = 
as λ Green > λ blue .
⇒ β Green > β blue ⇒ X Green > X blue
Also get 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The contrast in the fringes in any interference pattern depends on :
Yellow light emitted by sodium lamp in Young’s double slit experiment is replaced by monochromatic …
Young's experiment is performed in air and then performed in water, the fringe width:-
In Young's double slit experiment, the phase difference between the light waves reaching third brig…
Interference was observed in interference chamber when air was present, now the chamber is evacuate…
In double slits experiment, for light of which colour the fringe width will be minimum:-