A two slit Young’s interference experiment is done with monochromatic light of wavelength 6000 Å. The slits are 2 mm apart. The fringes are observed on a screen placed 10 cm away from the slits. Now a transparent plate of thickness 0.5 mm is placed in front of one of the slits and it is found that the interference pattern shifts by 5 mm. The refractive index of the transparent plate is :
Text Solution
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Clearly the central maxima at P(initially) shifts to P’ where PP’ = 5 mm.
So now, path difference at P’ must be zero.
⇒ d sin θ = ( μ – 1)t
⇒ d tan θ = ( μ – 1)t
μ = 1 + 
; get μ = 1.2
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