In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wavelength λ ) , the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate is:
Text Solution
Verified by ExpertsThe correct answer is:
A
Path difference due to slab should be integral multiple of λ or
Δ x = n λ
or ( μ – 1) t = n λ n = 1, 2, 3, ....
or t = 
For minimum value of t, n = 1
∴ t =
=
= 2 λ
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