In a YDSE arrangement composite lights of different wavelengths λ 1 = 560 nm and
λ 2 = 400 nm are used.If D = 1m, d = 0.1 mm. Then the distance between two completely dark regions is
Text Solution
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Let nth minima of 400 nm coincides with m th minima of 560 nm, then
(2n – 1) 
= (2m – 1) 
or 
= 
= 
=.........
i.e. 4th minima of 400 nm coincides with 3rd minima of 560 nm.
Location of this minima is,
Y 1 = 
= 14 mm
Next 11th minima of 400 nm will coincide with 8th minima of 560 nm.
Location of this minima is,
Y 2 = 
= 42 mm
∴ Required distance = Y 2 – Y 1 = 28 mm
Hence, the correct option is .
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