A spring executes SHM with mass of 10 kg attached to it. The force constant of spring is 10 N /m. If at any instant its velocity is 40 cm/sec, the displacement will be (where amplitude is 0.5 m):
Text Solution
Verified by ExpertsThe correct answer is:
B
Time period of spring is given by
T = 2 π 
⇒ = 
= 
∴ ꞷ = 
= 1
Velocity of mass at displacement x
u = ꞷ 
⇒ y 2 = a 2 – 
0
= (50) 2 – 
= (50) 2 – (40) 2
= (50 + 40) (50 – 40) = 900
∴ y = 30 cm = 0.3
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