Referring to the given circuit, match column-I with column-II:

Column-IColumn-II(i) For ω = 8000 r…

Question

Referring to the given circuit, match column-I with column-II:

Column-IColumn-II(i) For ω = 8000 rad/s[A] Peak current in the circuit is less than 0.1 A(ii) For ω = 10000 rad/s[B] Voltage across the combination and the current are in same phase(iii) For ω = 10500 rad/s[C] Voltage across the combination leads the current(iv) For ω = 10000 rad/s, if R = 50 Ω instead of 100 Ω[D] Current through the circuit leads the voltage across it

CGP EDU Academic Team · Accepted Answer

The correct answer is C. Step 1: Analyze the circuit at varying angular frequencies (ω) for the given RLC circuit.  Step 2: At ω = 8000 rad/s, since the impedance is mostly resistive, the peak current is likely to be low due to high impedance from the inductor. Hence, it corresponds to statement A.  Step 3: At ω = 10000 rad/s, the inductive reactance and resistance create a situation where voltage and current are approximately in phase, corresponding to statement B.  Step 4: At ω = 10500 rad/s, the inductive reactance dominates, leading the voltage across the combination to lead the current, corresponding to statement C.  Step 5: For R = 50 Ω instead of 100 Ω at ω = 10000 rad/s, the reduced resistance leads to an increase in current, which will now be leading voltage across it, corresponding to statement D.  Thus, the matches are: (i) [A], (ii) [B], (iii) [C], (iv) [D]. Therefore, the answer is C.

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Column-I	Column-II
(i) For ω = 8000 rad/s	[A] Peak current in the circuit is less than 0.1 A
(ii) For ω = 10000 rad/s	[B] Voltage across the combination and the current are in same phase
(iii) For ω = 10500 rad/s	[C] Voltage across the combination leads the current
(iv) For ω = 10000 rad/s, if R = 50 Ω instead of 100 Ω	[D] Current through the circuit leads the voltage across it

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