A particle is moving along x axis with constant acceleration. At t = 0, the particle is at x = 3 m and
= + 4 m/s. The maximum value of x co-ordinate of the particle is observed 2 seconds later. Starting from t = 0 sec after what time particle reaches its initial position again?
Text Solution
Verified by ExpertsThe correct answer is:
A
A constant acceleration is always towards –ve x direction so time to reach from A to B is same as time taken from B to A so total time t A → B → A = 4 sec.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle is moving with velocity 5 m/s towards east and its velocity changes to 5 m/s north in 10…
The displacement-time relationship for a particle is given by . The acceleration of the particle is
A particle has velocity given by v = 20 + 0.1 t 2 then it has
The displacement is given by x = 2t 2 + t + 5, the acceleration at t = 5 sec will be
A particle is moving so that its displacement is given as meter. Its velocity at the instant when …
If velocity of a particle is given by . The average acceleration between 2 and 5 s is