Juggler keeps on moving four balls in the air continuously such that each ball attains 20 m height. When the first ball leaves his hand, the position of the other balls (in meter height) will be
Text Solution
Verified by ExpertsThe correct answer is:
B
Time of flight – T = 
maximum height H = 
= 20m
u = 20 m/s T = 4 sec
Time gap between each ball = 1 sec
h 1 = ut 1 – 
gt 1 2 = 20 × 1 – 
× 10 2 = 20 – 5 = 15m
h 2 = ut 2 – 
gt 2 2
= 20 × 2 – 
× 10(b) 2 = 40 – 20 = 20m
h 3 = ut 3 – 
gt 3 2
= 20 × 3 – 
× 10(c) 2 = 60 – 45 = 15 m
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