A ball is thrown vertically upward. It has a speed of 10 m/s when it has reached one half of its maximum height. How high does the ball rise? (Taking g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
B
The problem can be solved using third equation of motion at A and O'.
Let maximum height attained by the ball be H. Third equation of motion gives
v 2 = u 2 – 2gh
At A, (10) 2 = u 2 – 2 × 10 × 
⇒ v 2 = 100 + 10H … (i)
At O', (0) 2 = u 2 – 2 × 10 × H
⇒ u 2 = 20 H
Thus, from Eqs. (i) and (ii), we get
20H = 100 + 10H
⇒ 10H = 100 ∴ H = 10 m
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