A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two ball meet at t = 18s. What is the value of v? [take g = 10 ms –2 ]
Text Solution
Verified by ExpertsThe correct answer is:
A
Let the two balls meet after 
at distance 
from the platform.
For the first ball
For the second ball 
From equations (i) and (ii), we get
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