When a current of 1 ampere is passed in a coil lying in the magnetic meridian then a magnetic needle at its centre gives some deflection. If the current in the coil is increased to 
ampere then at what distance from the centre of the coil will the deflection of needle remains unchanged?
Text Solution
Verified by ExpertsThe correct answer is:
D
...(i)
B = 
...(ii)
from (i) and (ii)
(R 2 + x 2 ) 3/2 = 
(R 2 + x 2 ) 3 = 8R 6 = (2R 2 ) 3
R 2 + x 2 = 2R 2
x 2 = R 2
⇒ x = ± R
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