A

Step 1: The radius of the circular path of a charged particle in a magnetic field is given by the formula:
$$ r = \frac{mv}{qB} $$
where:
- $r$ is the radius
- $m$ is the mass of the particle
- $v$ is the speed of the particle
- $q$ is the charge of the particle
- $B$ is the magnetic field strength

Since the speed $v$ and the magnetic field $B$ are the same for both ions, we can focus on the mass and charge for each ion to find the ratio of their radii.

Step 2: For ion 1:
Given that $A_1 = 24$ and $q_1 = e$, we can represent the mass and charge as $m_1 = 24$ and $q_1 = e$.
The radius for ion 1:
$$ r_1 = \frac{m_1 v}{q_1 B} = \frac{24v}{eB} $$

Step 3: For ion 2:
Given that $A_0 = 22$ and $q_2 = 2e$, we can represent the mass and charge as $m_2 = 22$ and $q_2 = 2e$.
The radius for ion 2:
$$ r_2 = \frac{m_2 v}{q_2 B} = \frac{22v}{2eB} = \frac{11v}{eB} $$

Step 4: Now, we need to find the ratio of their radii:
$$ \frac{r_1}{r_2} = \frac{\frac{24v}{eB}}{\frac{11v}{eB}} = \frac{24}{11} $$

So, the radius ratio $\frac{r_1}{r_2}$ is $\frac{24}{11}$. Hence, the correct answer is Option B: 24/11.