A wire EF carrying current i1 is placed near a current carrying rectangular loop ABCD as shown. Then the wire EF

Text Solution
Verified by ExpertsThe correct answer is:
B
For parallel wires, same direction currents attract and opposite currents repel.
The magnetic force between two parallel wires ∝ 
AB and CD are symmetrical relative to wire EF, so, they exert equal and opposite forces on EF.
As wire BC is nearer to EF as compared to AD and current in both wires is same, so wire BC exerts larger force than that of AD. So, wire EF will be attracted towards the loop.
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