The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be J. (Given R = 8.31 J/mol.K)
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(7479)
U = nC v T
= 2x 
Rx300
= 900R = 900x8-31 =74791
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