A mass of 10 kg is suspended vertically by a rope of length 5m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is 
= tan -1 (x x 10 -1 ). The value of x is _________ .
(Given g= 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(3)
T sin 
= 30
T cos 
= 100
tan 9 = 0.3
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