Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A body is performing simple harmonic with an amplitude of 10 cm. The velocity of the body was tripled by air Jet when it is at 5 cm from its mean position. The new amplitude of vibration is 
cm. The value of x is__________.
Text Solution
Verified by ExpertsThe correct answer is:
700
(700)
A = 10 cm
Total Energy = 
KA 2
By energy conservation we can final v at x = 5
Now, velocity is tripled through external mean so the amplitude of SHM will charge and so the total energy, (but potential) energy at this moment will remain same)
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