The electric field at the point associated with a light wave is given by
E = 200 [sin(6 x 10 15 ) t + sin(9 x 10 15 ) t] Vm -1 Given: h = 4.14x10
-I5 eVs
If this light falls on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be:
Text Solution
Verified by ExpertsThe correct answer is:
D
For maximum KE we will take
higher frequency 
3.43 eV nearest is 3.42 eV
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