When a ball is dropped into a lake from a height 4.9 m above the water level, it hits the water with a velocity v and then sinks to the bottom with the constant velocity v. It reaches the bottom of the lake 4.0 s after it is dropped. The approximate depth of the lake is:
Text Solution
Verified by ExpertsThe correct answer is:
B
V 2 =2x9.8x4.9
V = 9.8m/s
Depth = distance travelled in 3 seconds
= 9.8 x3 = 29.4m
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