Published by:
CGP EDU Academic Team
Published on: September 11, 2026
A block of ice of mass 120 g at temperature 0°C is put in 300 gm of water at 25°C. The xg of ice melts as the temperature of the water reaches 0°C. The value of x is [Use: Specific heat capacity of water = 4200 Jkg -1 K -1 , Latent heat of ice = 3.5 x 10 5 Jkg -1 ]
Text Solution
Verified by ExpertsThe correct answer is:
90
(90)
Sol. Energy released by water
= 0.3x25x4200 = 31500J
let m kg ice melts
mx3.5x10 5 = 31500
m = 0.09 kg = 90 gm
x = 90
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