Three masses M = 100 kg, m 1 = 10 kg and m 2 = 20 kg are arranged in a system as shown in figure. All the surfaces are frictionless and strings are inextensible and weightless. The pulleys are also weightless and frictionless. A force F is applied on the system so that the mass m 2 moves upward with an acceleration of 2 ms -2 . The value of F is:
(Take g= 10ms -2 )
Text Solution
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Let acceleration of 100 kg block = a 1
FED of 100 kg block w.r.t ground
F-T-N 1 = 100a 1 . ....(i)
T-20g=20(2)
T=240…(i)
N 1 =20a 1 .....(iii)
FED of 10 kg block w.r.t 100 kg
10a 1 -240 = 10(2)
a 1 =26m/s 2
F-240-20(26) = 100x26
F = 3360 N
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