A slab of stone of area 0.36 m 2 and thickness 0.1 m is exposed on the lower surface to steam at 100°C. A block of ice at 0°C rests on the upper surface of the slab. In one hour 4.8 kg of ice is melted. The thermal conductivity of slab is: (Given latent heat of fusion of ice = 3.36 × 10 5 J kg –1 ):
Text Solution
Verified by ExpertsThe correct answer is:
A
Rate of heat given by steam = Rate of heat taken by ice
K = 1.24 J/m/s/°C
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