One end of massless rope, which passes over a massless and frictionless pulley P is tied to a hook C while the other end is free. Maximum tension that the rope can bear is 360 N. With what value of minimum safe acceleration (in ms -2 ) can a man of 60 kg climb down the rope
Text Solution
Verified by ExpertsThe correct answer is:
C
FBD
T – mg = ma
360 – 60× 10 = 60 × a
i.e. slip through the rope with a minimum acceleration 4m/s 2 .
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The linear momentum P of a body varies with time and is given by the equation P = x + yt 2 where x …
In which of the following cases forces must not be required to keep the-
The average force necessary to stop a hammer having momentum 25 N-s in 0.05 second is-
Two masses of 5 kg and 10 kg are connected to a pulley as shown. What will be the acceleration if t…
Two bodies of 5 kg and 4 kg are tied to a string as shown in the fig. If the table and pulley both …
The mass of ship is 2 × 107 kg. On applying a force of 25 × 105 N, it is displaced through 25m. Aft…