Two small masses m 1 and m 2 are at rest on a frictionless, fixed triangular wedge whose angles are 30° and 60° as shown. They are connected by a light inextensible string. The side BC of wedge is horizontal and both the masses are 1 meter vertically above the horizontal side BC of wedge. There is no friction between the wedge and both the masses. If the string is cut, which mass reaches the bottom of the wedge first? (Take g = 10m/s 2 )
Text Solution
Verified by ExpertsA
The vertical component of acceleration of mass 1 and mass 2 are
a 1 = g sin 2 60, a 2 = g sin 2 30
since vertical displacement for both masses is 1m, the block with larger acceleration will reach the base
of wedge first. Hence block of mass m 1 shall reach base of wedge first.
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