A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration 'a' directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration ' a ' (relative to car) vertically. The tension in the string is equal to
A
m 
B
m 
– ma
– ma
C
m 
+ ma
+ ma
D
m (g + a)
Text Solution
Verified by ExpertsThe correct answer is:
C
(Force diagram in the frame of the car)
Applying Newton’s law perpendicular to string
mg sin θ = ma cos θ
tan θ = 
Applying Newton’s law along string = T – m 
= ma
T = m 
+ ma
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