Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration 'a' directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration ' a ' (relative to car) vertically. The tension in the string is equal to
A
m 
B
m 
– ma
– ma
C
m 
+ ma
+ ma
D
m (g + a)
Text Solution
Verified by ExpertsThe correct answer is:
C
(Force diagram in the frame of the car)
Applying Newton’s law perpendicular to string
mg sin θ = ma cos θ
tan θ = 
Applying Newton’s law along string = T – m 
= ma
T = m 
+ ma
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A vessel containing water is given a constant acceleration a towards the right, along a straight ho…
A ship of mass \(3 \times 10^{7} \, \text{kg}\) initially at rest is pulled by a force of \(5 \time…
The mass of a body measured by a physical balance in a lift at rest is found to be m. If the lift i…
Three weights W, 2W and 3W are connected to identical springs suspended from a rigid horizontal rod…
When forces F_1, F_2, F_3 are acting on a particle of mass m such that F_2 and F_3 are mutually per…
The spring balance A reads 2 kg with a block m suspended from it. A balance B reads 5 kg when a bea…