Published by:
CGP EDU Academic Team
Published on: September 12, 2026
At what other angle of elevation, the range of a shell fired from a gun will be the same as that for an angle of elevation 5π/36?
Text Solution
Verified by ExpertsThe correct answer is:
C
Step 1: Understand the Range Formula
The range R of a projectile fired at an angle θ with respect to the horizontal is given by the formula:
$$R = \frac{v^2 \sin(2\theta)}{g}$$
where v is the initial velocity and g is the acceleration due to gravity.
Step 2: Analyze the Given Angle
We know that the range is identical for angles θ and (π/2 - θ) due to the property of the sine function. Thus, if θ = 5π/36, we can find the complementary angle:
$$\text{Complementary angle} = \frac{\pi}{2} - \theta = \frac{\pi}{2} - \frac{5\pi}{36}$$
To find this, convert \frac{\pi}{2}$ to a fraction with a common denominator of 36:
$$\frac{\pi}{2} = \frac{18\pi}{36}$$
Then calculate:
$$\frac{\pi}{2} - \frac{5\pi}{36} = \frac{18\pi}{36} - \frac{5\pi}{36} = \frac{13\pi}{36}$$
Step 3: Conclusion
The angle that will yield the same range as an elevation of 5π/36 is 13π/36. This corresponds to option C.
The range R of a projectile fired at an angle θ with respect to the horizontal is given by the formula:
$$R = \frac{v^2 \sin(2\theta)}{g}$$
where v is the initial velocity and g is the acceleration due to gravity.
Step 2: Analyze the Given Angle
We know that the range is identical for angles θ and (π/2 - θ) due to the property of the sine function. Thus, if θ = 5π/36, we can find the complementary angle:
$$\text{Complementary angle} = \frac{\pi}{2} - \theta = \frac{\pi}{2} - \frac{5\pi}{36}$$
To find this, convert \frac{\pi}{2}$ to a fraction with a common denominator of 36:
$$\frac{\pi}{2} = \frac{18\pi}{36}$$
Then calculate:
$$\frac{\pi}{2} - \frac{5\pi}{36} = \frac{18\pi}{36} - \frac{5\pi}{36} = \frac{13\pi}{36}$$
Step 3: Conclusion
The angle that will yield the same range as an elevation of 5π/36 is 13π/36. This corresponds to option C.
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