A particle of mass m is projected making angle 45º with horizontal having kinetic energy K. The kinetic energy at highest point will be - (Kinetic energy = 
)
A
B
C
2 K
D
K
Text Solution
Verified by ExpertsThe correct answer is:
B
At highest point of projection, the vertical component of velocity is zero and there is only horizontal component of velocity.
At the highest point
V x = u cos θ
V y = 0
K H = 
or K H = 
...........(i)
Intial kinetic energy is
K = 
.........(ii)
From Eq. (i) and (ii), we get
K H = K cos 2 θ = K cos 2 45°
= 
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