C

Step 1: Identify the components of motion. The horizontal and vertical components of the velocity are given as 9.8 m/s and 19.6 m/s, respectively.
Step 2: Determine the time of flight. The time of flight can be found using the vertical component of velocity. The time to reach the highest point of the projectile can be calculated using the formula for vertical motion:
$$ t_{up} = \frac{v_{y}}{g} = \frac{19.6 \text{ m/s}}{9.8 \text{ m/s}^2} = 2 \text{ s} $$
The total time of flight is double this value (up and down):
$$ t_{total} = 2 \cdot t_{up} = 2 \cdot 2 = 4 \text{ s} $$
Step 3: Calculate the horizontal range. The horizontal range (R) can be calculated as:
$$ R = v_{x} \cdot t_{total} = 9.8 \text{ m/s} \cdot 4 \text{ s} = 39.2 ext{ m} $$
Therefore, the horizontal range is 39.2 m.
Thus, the correct answer is C.