A particle moves in the xy plane with only an x-component of acceleration of 2 m s –2 . The particle starts from the origin at t = 0 with an initial velocity having an x-component of 8 m s –1 and y-component of –15 ms –1 . Velocity of particle after time t is :
A
[(8 + 2t) 
– 15 
]
– 15 ]
B
zero
C
2t + 15
D
directed along z-axis.
Text Solution
Verified by ExpertsThe correct answer is:
A
a x = 2 m/s 2 ; ay = 0
u x = 8 m/s
u y = – 15 m/s.
= V x + V y
V y = u y + a y t
⇒ V y = – 15 m/s
V x = u x + a x t
V x = 8 + 2
⇒ V = [(8 + 2t) 
– 15 
] m/s.
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