The horizontal and verticle distances travelled by a particle in time t are given by x = 6t and
y = 8t – 5t 2 . If g = 10 m/sec 2 , then the initial velocity of the particle is-
Text Solution
Verified by ExpertsThe correct answer is:
B
x = 6t, y = 8t – 5t 2
= 6, 
= 8 – 10t
at t = 0
V x = 6 m/sec, V y = 8m/sec
V = 
= 
= 10 m/sec
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