A

Step 1: Understand the range and time of flight. The range (R) of the projectile is given as 200 meters and the time of flight (T) is 5 seconds.
Step 2: The horizontal component of the velocity (V_x) can be calculated using the formula for range in projectile motion, which is:
$$ R = V_x imes T $$
Rearranging the formula gives us:
$$ V_x = \frac{R}{T} $$
Step 3: Substitute the known values into the equation:
$$ V_x = \frac{200 ext{ m}}{5 ext{ s}} = 40 ext{ m/s} $$
Step 4: Conclude that the horizontal component of the velocity of the arrow is 40 m/s.
Therefore, the correct answer is B.