B

Step 1: The initial velocity at point A is given as \(2\hat{i} + 3\hat{j}\) m/s.
Step 2: At point B, the projectile's motion changes due to gravity. This affects only the y-component of the velocity.
Step 3: The y-component of velocity is affected by the gravitational acceleration, which is typically taken as \(g = 9.8 \text{ m/s}^2\) downward.
Therefore, the new y-component at point B becomes:
\[ v_{yB} = v_{yA} - gt = 3 - g \cdot t \]
Step 4: Assuming the projectile has been ascending before reaching point B, we calculate the velocity components at point B. If the total time of flight is not provided, we will assume a perfect arc where it has returned to similar horizontal levels:
Thus, the corrected velocity at point B would then be \(-2\hat{i} + 3\hat{j}\) m/s.
Step 5: After examining possible answers, we find that this matches the form in Option B.
Hence, the answer is B.