Three elephants A, B and C are moving along a straight line with constant speed in same direction as shown in figure. Speed of A is 5 m/s and speed of C is 10 m/s. Initially separation between A & B is ‘d’ and between B & C is also d. When ‘B’ catches ‘C’ separation between A & C becomes 3d. Then the speed of B will be -
Text Solution
Verified by ExpertsThe correct answer is:
B
B catches C in time t then t = 
Separation by this time has increased by 'd' between A and C hence
(10 – 5) × 
= d
u = 15 m/s
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