A

Step 1: The energy (E) of a photon is given by the relation:
$$ E = \frac{hc}{\lambda} $$
where:

• h is Planck's constant,
• c is the speed of light,
• \( \lambda \) is the wavelength of the photon.

Step 2: From this equation, we can see that as the wavelength \( \lambda \) decreases, the energy E of the photon increases.
Step 3: Now, the linear momentum (p) of a photon is given by the equation:
$$ p = \frac{E}{c} $$
Step 4: Since the energy E is increasing with a decrease in wavelength, it follows that the linear momentum p will also increase.
Conclusion: Therefore, both the momentum p and energy E of the photon increase when the wavelength decreases.
Therefore, the correct answer is A.