A steel rod is projecting out of a rigid wall. The shearing strength of steel is 345 MN m -2 . The dimensions AB = 5 cm, BC = BE = 2 cm. The maximum load that can be put on the face ABCD is : (neglect bending of the rod) (g = 10 m s -2 )
Text Solution
Verified by ExpertsThe correct answer is:
C
F = shear strength x area on which shear stress acts
= 345 x 10 6 x 4 x 10 -4
= 138000 N
So the mass that can be placed = 13800 kg
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