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CGP EDU Academic Team
Published on: September 12, 2026
A boy weighing 50 kg eat some bananas. The energy content of the bananas is 1000 cal. If the boy uses all of this energy to jump upwards from the ground, then the height up to which his centre of mass will rise is [mechanical equivalent of heat = 4. 2 J cal -1 , g = 10 m s -2 ]
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Convert energy from calories to Joules. The energy content of the bananas is 1000 cal. Using the mechanical equivalent of heat:
\( 1000 \text{ cal} \times 4.2 \text{ J/cal} = 4200 \text{ J}
Step 2: Use the potential energy formula. The potential energy (PE) when the boy jumps is given by:
\( PE = mgh \)
where \( m = 50 \text{ kg} \), \( g = 10 \text{ m/s}^2 \), and \( h \) is the height.
Setting the energy used to the potential energy:
\( 4200 = 50 \times 10 \times h
\( 4200 = 500h
\( h = \frac{4200}{500} = 8.4 ext{ m}
Step 3: Conclude. Therefore, the height he can jump is 8.4 m.
\( 1000 \text{ cal} \times 4.2 \text{ J/cal} = 4200 \text{ J}
Step 2: Use the potential energy formula. The potential energy (PE) when the boy jumps is given by:
\( PE = mgh \)
where \( m = 50 \text{ kg} \), \( g = 10 \text{ m/s}^2 \), and \( h \) is the height.
Setting the energy used to the potential energy:
\( 4200 = 50 \times 10 \times h
\( 4200 = 500h
\( h = \frac{4200}{500} = 8.4 ext{ m}
Step 3: Conclude. Therefore, the height he can jump is 8.4 m.
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