In a standard Young's double-slit experiment, how many maxima can be obtained on a screen (including central maxima), if the distance between the silts is 
(where 
is the wavelength of light)?
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
5
In YDSE, path difference, 
x = d sin 
maxima, 
, where n = 0, ±1, ±2....
(given that d = 
)
….(i)
Since, -I<sin 
<l From (i) 
So, 
So, possible values of n are -2, -1, 0, 1,2 Thus a total of 5 maximas will be obtained.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In Young's double slit experiment, how many maxima can be obtained on a screen (including central m…
A vessel ABCD of 10 cm width has two small slits S 1 and S 2 sealed with identical glass plates of …
A screen is at a distance D = 80 cm from a diaphragm having two narrow slits S 1 and S 2 which are …
A ray of light of intensity I is incident on a parallel glass-slab at the point A and it undergoes …
In Young's double-slit experiment, the ratio of intensities of a bright band and a dark band is 16 …
Two beams of light having intensities I and 4I, interfere to produce a fringe pattern on a screen. …