A block A of mass m is in equilibrium after being suspended from the ceiling with the help of a spring of force constant k. The block B of mass m, strikes the block A with a speed v and sticks to it. The value of v for which the spring just attains its natural length is

Text Solution
Verified by ExpertsThe correct answer is:
A
( a ) Let the velocity of the combined system just after the collision is v’ then using conservation of linear momentum we get
mv = 2mv’,
Now, using the conservation of mechanical energy we get

Initial elongation of the spring is



Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two particles of equal mass have velocities and . First particle has an acceleration , while the…
A particle of mass 2 kg moving with a speed of 6 m/s collides elastically with another particle of …
A 500 g ball is released from a height of 4 m. Each time it contacts the ground, it loses 25% of it…
A massive vertical wall is approaching a man at a speed u. When it is at a distance of 10 m, the ma…
A neutron collides elastically with the stationary nucleus of an atom of mass number A. If the coll…
Two particles of equal mass m are moving with velocities and respectively. If the particles colli…