A block of mass 1 kg is pushed towards another block of mass 2 kg from a 6 m distance as shown in the figure. If just after the collision, the velocity of 2 kg block is 4 m s -l , then
Text Solution
Verified by ExpertsThe correct answer is:
A
Coefficient of restitution between the blocks is 1
From conservation of linear momentum, we can see that velocity of 1 kg block just after collision is 2 m/s
leftwards.
Now relative velocity of approach = 6 m/s
and relative velocity of separation = 6 m/s
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