In an experiment for determination of refractive index of glass of a prism by i – δ , plot, it was found that a ray incident at angle 35º, suffers a deviation of 40º and that it emerges at angle 79º. In that case which of the following is closest to the maximum possible value of the refractive index ?
Text Solution
Verified by ExpertsThe correct answer is:
D
When tc i = 35° and e = 79° then rc δ = 40°
δ = i + e – A
40° = 35 + 79 – A
A = 74°
Since i ≠ e so δ min will less than 40°
n = 
n = 
Since δ min will be less than 40° so
n will be less than 1.4
so the closest answer will be 1.5
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