A convex lens is put 10 cm from a light source and it makes a sharp image on a screen, kept 10 cm from the lens. Now a glass block (refractive index 1.5) of 1.5 cm thickness is placed in contact with the light source. To get the sharp image again,, the screen is shifted by a distance d. Then d is :
Text Solution
Verified by ExpertsThe correct answer is:
B

2f = 10 cm so f = 5 cm
Now due to glass plate shift iV~ =
= 1.5
= 0.5cm
So new u = 10 – 0.5 = 9.5 cm




So, shift
cm away from the lens
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