The external and internal diameters of a hollow cylinder are measured to be (4.23 ± 0.01) cm and (3.89 ± 0.01) cm. The thickness of the wall of the cylinder is
Text Solution
Verified by ExpertsThe correct answer is:
C
D = (4.23 ± 0.01) cm
d = (3.89 ± 0.01) cm
Δ t = (D – d)/2
= 
= 
= (0.34 ± 0.02)/2 cm
= (0.17 ± 0.01)cm
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