The energy of a system as a function of time t is given as E(t) = A 2 exp(–at), where a = 0.2s –1 . The measurement of A has an error of 1.25%. If the error in the measurement of time is 1.50%, the percentage error in the value of E(t) at t = 5 s is
Text Solution
Verified by ExpertsThe correct answer is:
D
E(t) = A 2 e–αt
α = 0.2 s–1
= 1.25%
= 1.50 %
= ?
log E = 2 log A – αt
= ± 2 
± αdt
= ±2 (1.25) ± 0.2(7.5)
= ± 2.5 ± 1.5
= ± 4 %
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The period of oscillation of a simple pendulum is given by where l is about 100 cm and is known to…
The percentage errors in the measurement of mass and speed are 2% and 3% respectively. How much wil…
The random error in the arithmetic mean of 100 observations is x ; then random error in the arithme…
Error in the measurement of radius of a sphere is 1%. The error in the calculated value of its volu…
The mean time period of second 's pendulum is 2.00 s and mean absolute error in the time period is …
A body travels uniformly a distance of (13.8 ± ± 0.2) m in a time (4.0 ± ± 0.3) s. The velocity of …