Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A resistor dissipates 192J of energy in 1s when a current of 4A is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in 5s in..... J.
Text Solution
Verified by ExpertsThe correct answer is:
3840
(3840)
E = i 2 Rt
192 = 16(R)(1)
R = 12Ω
E 1 = (8) 2 (12)(5)
= 3840 J
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