Home Physics Semiconductor Electronics JEE Main 2021 A Zener diode of power rating 2W is to be us…
Physics Semiconductor Electronics JEE Main 2021 MCQ (Single Correct)

A Zener diode of power rating 2W is to be used as a voltage regulator. If the Zener diode has a breakdown of 10V and it has to regulate voltage fluctuated between 6V and 14V, the value of R s for safe operation should be

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(20)

When unregulated voltage is 14V voltage across Zener diode must be 10V So potential difference across resistor ΔV Rs = 4 V and P zener = 2 W

VI = 2

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.