Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A person standing on a spring balance inside a stationary lift measures
. The weight of that person if thelift descends with uniform downward acceleration of
will be ___ 
Text Solution
Verified by ExpertsThe correct answer is:
C
To calculate the weight measured on the spring balance when a person is in a descending lift with uniform acceleration, we need to consider the effective weight of the person during acceleration.
1. **Given Data**:
- Mass of the person (m) = 60 kg
- Acceleration of lift (a) = 1.8 m/s²
- Acceleration due to gravity (g) = 10 m/s²
2. **Weight Calculation**:
The effective weight (W') can be calculated using the formula:
$$ W' = m(g - a) $$
where:
- W' is the effective weight
- m is the mass
- g is the acceleration due to gravity
- a is the downward acceleration of the lift.
3. **Substituting Values**:
$$ W' = 60 imes (10 - 1.8) $$
$$ W' = 60 imes 8.2 $$
$$ W' = 492 ext{ N} $$
Therefore, the weight of the person as measured by the spring balance will be **492 N**.
1. **Given Data**:
- Mass of the person (m) = 60 kg
- Acceleration of lift (a) = 1.8 m/s²
- Acceleration due to gravity (g) = 10 m/s²
2. **Weight Calculation**:
The effective weight (W') can be calculated using the formula:
$$ W' = m(g - a) $$
where:
- W' is the effective weight
- m is the mass
- g is the acceleration due to gravity
- a is the downward acceleration of the lift.
3. **Substituting Values**:
$$ W' = 60 imes (10 - 1.8) $$
$$ W' = 60 imes 8.2 $$
$$ W' = 492 ext{ N} $$
Therefore, the weight of the person as measured by the spring balance will be **492 N**.
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