Both A & B are thrown simultaneously as shown from a very high tower.
Column I Column II
A
(P) Distance between the two balls at two seconds is 
m.
B
(Q) distance between two balls at 2 seconds is 40 m.
C
(R) distance between two balls at 2 sec is 
m.
D
(S) Magnitude of relative velocity of B w.r.t A is 
m/s. (T) magnitude of relative velocity of B with respect to A is 
m/s.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
Q, R,T P Q
Sol. V BA = 10 + 10 = 20
so distance b/w B and A in 2sec. = 2 × 20 = 40 m
= 
⇒ | V BA | = 
= 
distance between A and B in 2 sec. = 
m
:- 
so | 
| = 
so distance between A and B in 2 sec. = 2 × 
= 
: - 
so | 
| = 20
so distance between A and B in 2 sec. = 2 × 20 = 40 m
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