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Physics Motion in a Straight Line Relative Motion MCQ (Single Correct)

A man in a lift which is ascending with an upward acceleration 'a' throws a ball vertically upwards with a velocity ‘v’ with respect to himself and catches it after ‘t 1 ’ seconds. Afterwards when the lift is descending with the same acceleration 'a' acting downwards the man again throws the ball vertically upwards with the same velocity with respect to him and catches it after ‘t 2 ’ seconds

A
the acceleration of the ball with respect to ground is g when it is in air
B
the velocity v of the ball relative to the lift is
C
the acceleration 'a' of the lift is
D
the velocity ‘v’ of the ball relative to the man is

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The correct answer is:
CHECK THE SOLUTION

(a,c,d) For first case (when lift is ascending with an acceleration a)

t 1 = ...........(i)

for second case (when lift is descending with an acceleration a )

t 2 = ...........(ii)

on solving equation (i) and (ii) we get

V =

& a = g

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