Airplanes A and B are flying with constant velocity in the same vertical plane at angles 30° and 60° with respect to the horizontal respectively as shown in figure. The speed of A is 100
ms –1 . At time t = 0s, an observer in A finds B at a distance of 500m. This observer sees B moving with a constant velocity perpendicular to the line of motion of A. If at t = t 0 , A just escapes being hit by B, t 0 in seconds is:

Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
(5)
Sol.

For relative motion perpendicular to line of motion of A
V A = 100
= V B Cos 30º
⇒ V B = 100 m/s
t 0 = 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
An object moving with a speed of 6.25 m/s, is decelerated at a rate given by:
where v is the insta…
A particle of mass m is at rest at the origin at time t = 0. It is subjected to a force F(t) = F 0 …
From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by…
A body is thrown vertically upwards. Which one of the following graphs correctly represent the velo…
All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pi…
The position co-ordinates of a particle moving in a 3-D coordinate system is given by x = a cosωt, …