Assuming that the moon is a sphere of the same mean density as that of the earth and one quarter of its radius, the length of a seconds pendulum on the moon (its length on the earth’s surface is 99.2 cm) is
A
24.8 cm
B
49.6 cm
C
99.2
D
cm
Text Solution
Verified by ExpertsThe correct answer is:
A
g = 
= 
= 
G πρ R
g ∝ R
as Radius of the moon is one forth so g on moon is also one fourth.
Time period of a second pendulum on the earth
T = 2 π 
at moon T = 2 π 
dividing λ 1 = λ 
= λ 
λ 1 = 
= 24.8 cm
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